In these problems we will be attempting to factor

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Unformatted text preview: ne a couple of these we won’t put the remaining details in and we’ll go straight to the final factoring. x5 - 3 x3 - 2 x 2 + 6 = x 3 ( x 2 - 3) - 2 ( x 2 - 3) = ( x 2 - 3 ) ( x 3 - 2 ) [Return to Problems] Factoring by grouping can be nice, but it doesn’t work all that often. Notice that as we saw in the last two parts of this example if there is a “-” in front of the third term we will often also factor that out of the third and fourth terms when we group them. Factoring Quadratic Polynomials First, let’s note that quadratic is another term for second degree polynomial. So we know that the largest exponent in a quadratic polynomial will be a 2. In these problems we will be attempting to factor quadratic polynomials into two first degree (hence forth linear) polynomials. Until you become good at these, we usually end up doing these by trial and error although there are a couple of processes that can make them somewhat easier. Let’s take a look at some examples. Example 3 Factor each of the following polynomials....
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