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Unformatted text preview: 3 .
So, unlike the previous example we can’t just combine up the two regions into a single inequality
since that would include a point that isn’t part of the solution. Here is the solution for this
problem. 1 < x < 3 and 3< x <¥ ( 1,3) and ( 3, ¥ ) Now, all of the examples that we’ve worked to this point involved factorable polynomials.
However, that doesn’t have to be the case. We can work these inequalities even if the polynomial
doesn’t factor. We should work one of these just to show you how the work. Example 5 Solve 3 x 2  2 x  11 > 0 .
Solution
In this case the polynomial doesn’t factor so we can’t do that step. However, we do still need to
know where the polynomial is zero. We will have to use the quadratic formula for that. Here is
what the quadratic formula gives us. x= 1 ± 34
3 In order to work the problem we’ll need to reduce this to decimals. x= 1 + 34
= 2.27698
3 x= 1  34
= 1.61032
3 From this point on the process is identical to the previous examples. In the number line below the
dashed lines a...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
 Spring '12
 MrVinh

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