Lets take a look at an example here is the system of

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Unformatted text preview: the equations for one of the variables (it doesn’t matter which you choose). We’ll solve the first for y. 2 x + 5 y = -1 5 y = -2 x - 1 2 1 y = - x5 5 Then, given any x we can find a y and these two numbers will form a solution to the system of equations. We usually denote this by writing the solution as follows, © 2007 Paul Dawkins 322 http://tutorial.math.lamar.edu/terms.aspx College Algebra x=t where t is any real number 21 y=- t55 So show that these give solutions let’s work through a couple of values of t. t=0 x=0 y=- 1 5 To show that this is a solution we need to plug it into both equations in the system. æ 1ö ? æ 1ö ? 2 ( 0 ) + 5 ç - ÷ =- 1 - 10 ( 0 ) - 25 ç - ÷ = 5 è 5ø è 5ø - 1 = -1 5=5 1 So, x = 0 and y = - is a solution to the system. Let’s do another one real quick. 5 t=-3 x = -3 y=- 2 161 ( -3 ) - = - = 1 5 555 Again we need to plug it into both equations in the system to show that it’s a solution. 2 ( -3) + 5 (1) =- 1 - 10 ( -3) - 25 (1) = 5 - 1 = -1 5=5 ? ?...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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