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Unformatted text preview: too bad. ( f o g )( x) = f é g ( x )ù
é x 2ù
=fê + ú
æ x 2ö
= 3ç + ÷ - 2
=x Looks like things simplified down considerable here.
[Return to Problems] © 2007 Paul Dawkins 195 http://tutorial.math.lamar.edu/terms.aspx College Algebra (b) All we need to do here is use the formula so let’s do that. ( g o f ) ( x ) = g é f ( x )ù
= g [3x - 2] 1
( 3x - 2 ) +
= x- +
= So, in this case we get the same answer regardless of the order we did the composition in.
[Return to Problems] So, as we’ve seen from this last example it is possible to get the same answer from both
compositions on occasion. In fact when the answer from both composition is x, as it is in this
case, we know that these two functions are very special functions. In fact, they are so special that
we’re going to devote the whole next section to these kinds of functions. So, let’s move onto the
next section. © 2007 Paul Dawkins 196 http://tutorial.math.lamar.edu/terms.aspx College Algebra Inverse Functions
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12