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Unformatted text preview: he denominator as
completely as possible. Then for each factor in the denominator we can use the following table to
determine the term(s) we pick up in the partial fraction decomposition.
denominator Term in partial
fraction decomposition ax + b A
ax + b ( ax + b ) Ak
ax + b ( ax + b )
( ax + b ) k ax 2 + bx + c ( ax 2 + bx + c ) © 2007 Paul Dawkins Ax + B
ax + bx + c
Ak x + Bk
A1 x + B1
A2 x + B2
ax + bx + c ( ax 2 + bx + c )
( ax2 + bx + c )
2 k 271 http://tutorial.math.lamar.edu/terms.aspx College Algebra Notice that the first and third cases are really special cases of the second and fourth cases
respectively if we let k = 1 . Also, it will always be possible to factor any polynomial down into
a product of linear factors ( ax + b ) and quadratic factors ( ax 2 + bx + c ) some of which may be
raised to a power.
There are several methods for determining the coefficients for each term and we will go over each
of those as we work the examples. S...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12