Alg_Complete

Once this is solved we substitute this value back

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 00 into the equation. Q = 100e -0.000124 (1000 ) = 100 ( 0.883379840883) = 88.338 milligrams So, it looks like we will have around 88.338 milligrams left after 1000 years. [Return to Problems] (b) How long will it take for half of the Carbon 14 to decay? So, we want to know how long it will take until there is 50 milligrams of the Carbon 14 left. That means we will have to solve the following equation, 50 = 100e -0.000124 t Here is that work. © 2007 Paul Dawkins 312 http://tutorial.math.lamar.edu/terms.aspx College Algebra 50 = e-0.000124 t 100 1 = e-0.000124 t 2 1 ln = ln e -0.000124 t 2 1 ln = -0.000124 t 2 1 ln -0.69314718056 2 = = 5589.89661742 t= -0.000124 -0.000124 So, it looks like it will take about 5589.897 years for half of the Carbon 14 to decay. This number is called the half-life of Carbon 14. [Return to Problems] We’ve now looked at a couple of applications of exponential equations and we should now look at a quick application of a logarithm. Earthquake Intensity The Richter scale is commonly used to measure the intensity of an earthquake....
View Full Document

This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online