Return to problems now lets move onto multiplying

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Unformatted text preview: ltiplying a “-1” through the second polynomial using the distributive law. After distributing the minus through the parenthesis we again combine like terms. Here is the work for this problem. x 2 + x + 1 - ( 5 x 3 - 9 x 2 + x - 3) = x 2 + x + 1 - 5 x 3 + 9 x 2 - x + 3 = -5 x3 + 10 x 2 + 4 © 2007 Paul Dawkins 27 http://tutorial.math.lamar.edu/terms.aspx College Algebra Note that sometimes a term will completely drop out after combing like terms as the x did here. This will happen on occasion so don’t get excited about it when it does happen. [Return to Problems] Now let’s move onto multiplying polynomials. Again, it’s best to do these in an example. Example 2 Multiply each of the following. (a) 4 x 2 ( x 2 - 6 x + 2 ) [Solution] (b) ( 3 x + 5 ) ( x - 10 ) [Solution] ( ) (c) 4 x 2 - x ( 6 - 3 x ) [Solution] (d) ( 3 x + 7 y ) ( x - 2 y ) [Solution] ( ) (e) ( 2 x + 3) x 2 - x + 1 Solution (a) 4 x 2 x 2 - 6 x + 2 ( [Solution] ) This one is nothing more than a quick application of the distributive law. 4 x 2 ( x 2 - 6 x + 2 ) = 4 x 4 - 24 x 3 + 8 x...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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