Return to problems now we need to take a look at the

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Unformatted text preview: of 1 on the exponential. We can only use the facts to simplify this if there isn’t a coefficient on the exponential. So, divide both sides by 5 to get, e2 z +4 = 8 5 At this point we will take the logarithm of both sides using the natural logarithm since there is an e in the equation. æ8ö ln e 2 z + 4 = ln ç ÷ è5ø æ8ö 2 z + 4 = ln ç ÷ è5ø æ8ö 2 z = ln ç ÷ - 4 è5ø 1æ æ8ö ö 1 z = ç ln ç ÷ - 4 ÷ = ( 0.470003629 - 4 ) = -1.76499819 2è è5ø ø 2 [Return to Problems] Note that we could have used this second method on the first set of examples as well if we’d wanted to although the work would have been more complicated and prone to mistakes if we’d done that. © 2007 Paul Dawkins 301 http://tutorial.math.lamar.edu/terms.aspx College Algebra Solving Logarithm Equations In this section we will now take a look as solving logarithmic equations, or equations with logarithms in them. We will be looking at two specific types of equations here. In particular we will loo...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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