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Unformatted text preview: olution we want regions where the polynomial will be negative (that’s the middle
two here) or zero (that’s all three points that divide the regions). So, we can combine up the
middle two regions and the three points into a single inequality in this case. The solution, in both
inequality and interval notation form, is. -6 £ x £ 2 [ -6, 2] Example 4 Solve ( x + 1)( x - 3 ) > 0 .
The first couple of steps have already been done for us here. So, we can just straight into the
work. This polynomial will be zero at x = -1 and x = 3 . Here is the number line for this
problem. © 2007 Paul Dawkins 132 http://tutorial.math.lamar.edu/terms.aspx College Algebra Again, note that the regions don’t alternate in sign!
For our solution to this inequality we are looking for regions where the polynomial is positive
(that’s the last two in this case), however we don’t want values where the polynomial is zero this
time since we’ve got a strict inequality (>) in this problem. This means that we want the last two
regions, but not x =...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12