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In the previous example we solved for R, but there is no reason for not solving for one of the
other variables in the problems. For instance, consider the following example.
© 2007 Paul Dawkins 82 http://tutorial.math.lamar.edu/terms.aspx College Algebra æ 1 5aR ö
Example 3 Solve V = m ç ÷ for b.
èb m ø
The first couple of steps are identical here. First, we will multiply the m through the parenthesis
and then we will multiply both sides by b to clear the fractions. We’ve already done this work so
from the previous example we have, Vb - m = -5abR In this case we’ve got b’s on both sides of the equal sign and we need all terms with b’s in them
on one side of the equation and all other terms on the other side of the equation. In this case we
can eliminate the minus signs if we collect the b’s on the left side and the other terms on the right
side. Doing this gives, Vb + 5abR = m Now, both terms on the right side have a b in them so if we factor that out of both terms we arrive
at, b (V +...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12