This preview shows page 1. Sign up to view the full content.
Unformatted text preview: to do this step.
Now, this is where the process really starts differing from what we’ve seen to this point. We still
take onehalf the coefficient of x and square it. However, instead of adding this to both sides we
do the following with it. © 2007 Paul Dawkins 214 http://tutorial.math.lamar.edu/terms.aspx College Algebra 2 2
æ 6ö
ç  ÷ = ( 3 ) = 9
è 2ø
3ö
æ
f ( x ) = 2 ç x2  6 x + 9  9 + ÷
2ø
è We add and subtract this quantity inside the parenthesis as show. Note that all we are really
doing here is adding in zero since 99=0! The order listed here is important. We MUST add first
and then subtract.
The next step is to factor the first three terms and combine the last two as follows. 15 ö
2
æ
f ( x ) = 2 ç ( x  3)  ÷
2ø
è
As a final step we multiply the 2 back through. f ( x ) = 2 ( x  3)  15
2 And there we go.
[Return to Problems] (b) Be careful here. We don’t have a coefficient of 1 on the x2 term, we’ve got a coefficient of 1.
So, the process is identical outside of that so we won’t put in as muc...
View Full
Document
 Spring '12
 MrVinh

Click to edit the document details