So if we could factor higher degree polynomials we

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r there is another polynomial Q(x), called the quotient, with degree one less than the degree of P(x) and a number R, called the remainder, such that, P ( x) = ( x - r )Q ( x) + R Note as well that Q(x) and R are unique, or in other words, there is only one Q(x) and R that will work for a given P(x) and r. So, with the one example we’ve done to this point we can see that, Q ( x ) = 5 x 2 + 19 x + 76 and R = 310 Now, let’s work a couple more synthetic division problems. © 2007 Paul Dawkins 247 College Algebra Example 3 Use synthetic division to do each of the following divisions. (a) Divide 2 x 3 - 3 x - 5 by x + 2 [Solution] (b) Divide 4 x 4 - 10 x 2 + 1 by x - 6 [Solution] Solution (a) Divide 2 x 3 - 3 x - 5 by x + 2 Okay in this case we need to be a little careful here. We MUST divide by a term in the form x - r in order for this to work and that minus sign is absolutely required. So, we’re first going to need to write x + 2 as, x + 2 = x - ( -2 ) and in doing so we can see that r = -2 . We can now do syn...
View Full Document

This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online