So lets finish the problem 2007 paul dawkins 67

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Unformatted text preview: rks identical to the previous one so let’s do the work. ( 2 )( y - 3) 2 æ ö æ 10 - y ö 5 2 ÷ 2 y - 3) ç ÷=ç 2 ( )( ç 2 ( y - 3) ÷ ç ( y - 3 ) ÷ è øè ø 5 ( y - 3) = 2 (10 - y ) 5 y - 15 = 20 - 2 y 7 y = 35 y=5 Now the solution is not y = 3 so we won’t get division by zero with the solution which is a good thing. Finally, let’s do a quick verification. 5 10 - 5 ? =2 2 ( 5) - 6 5 - 6 ( 5 ) + 9 55 = 44 OK So we did the work correctly. [Return to Problems] (d) 2z 3 = +2 z + 3 z - 10 In this case it looks like the LCD is ( z + 3) ( z - 10 ) and it also looks like we will need to avoid z = -3 and z = 10 to make sure that we don’t get division by zero. Let’s get started on the work for this problem. ( z + 3)( z - 10 ) æ ç 2z ö æ 3 ö + 2 ÷ ( z + 3)( z - 10 ) ÷=ç è z + 3 ø è z - 10 ø 2 z ( z - 10 ) = 3 ( z + 3) + 2 ( z + 3)( z - 10 ) 2 z 2 - 20 z = 3z + 9 + 2 ( z 2 - 7 z - 30 ) At this point let’s pause and acknowledge that we’ve got a z2 in the work here. Do not get excited about that. Sometimes these will show up temporarily in these problems. You should only worry about it...
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