Alg_Complete

So we need to take a look at how to graph a parabola

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Unformatted text preview: r side of the vertex so we are officially done with finding the points. However, let’s talk a little bit about how to find a second point using the yintercept and the axis of symmetry since we will need to do that eventually. First, notice that the y-intercept has an x coordinate of 0 while the vertex has an x coordinate of 3. This means that the y-intercept is a distance of 3 to the right of the axis of symmetry since that will move straight up from the vertex. Now, the left part of the graph will be a mirror image of the right part of the graph. So, since there is a point at y = 10 that is a distance of 3 to the right of the axis of symmetry there must also be a point at y = 10 that is a distance of 3 to the left of the axis of symmetry. So, since the x coordinate of the vertex is -3 and this new point is a distance of 3 to the left its x © 2007 Paul Dawkins 208 http://tutorial.math.lamar.edu/terms.aspx College Algebra coordinate must be -6. The coordinates of this new point are th...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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