Alg_Complete

# That will happen on occasion now we will eliminate

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Unformatted text preview: ponent as we did in the previous section. We will then move the term to the denominator and drop the minus sign. w æ1ö -2ç ÷ è 4ø 1 4 16 v = 1æ 1 ö ç÷ 2è 4 ø w - 2v 1 2 1 8 1 = 1 8 1 2v w 2 [Return to Problems] (b) In this case we will first simplify the expression inside the parenthesis. æ 2 -2 ö 3 çxy ÷ 1 ç - -3 ÷ ç x 2y ÷ è ø - 1 7 æ 2 1 3ö x x2 y ÷ =ç 2 ç ÷ ç y3 ÷ è ø - 1 7 æ 2+ 1 3- 2 x 2y 3 =ç ç 1 ç è ö ÷ ÷ ÷ ø - 1 7 æ 5 7ö = ç x2 y 3 ÷ è ø - 1 7 Don’t worry if, after simplification, we don’t have a fraction anymore. That will happen on occasion. Now we will eliminate the negative in the exponent using property 7 and then we’ll use property 4 to finish the problem up. 2 æ 2 -3 ö xy ÷ ç ç - 1 -3 ÷ ç x 2y ÷ è ø - 1 7 = 1 æ 5 7ö 3 ç x2 y ÷ è ø 1 7 = 1 5 14 1 x y3 [Return to Problems] © 2007 Paul Dawkins 13 http://tutorial.math.lamar.edu/terms.aspx College Algebra We will leave this section with a warning about a common mistake that students make in regards to negati...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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