Unformatted text preview: umbers. In other words, we
only plug in real numbers and we only want real numbers back out as answers. So, since we
would get a complex number out of this we can’t plug -10 into this function.
[Return to Problems] (c) f ( 0 )
Not much to this one. f ( 0) = ( 0) - 2 ( 0) + 8 = 8
2 Again, don’t forget that this isn’t multiplication! For some reason students like to think of this
one as multiplication and get an answer of zero. Be careful.
[Return to Problems] (d) f ( t )
The rest of these evaluations are now going to be a little different. As this one shows we don’t
need to just have numbers in the parenthesis. However, evaluation works in exactly the same
way. We plug into the x’s on the right side of the equal sign whatever is in the parenthesis. In
this case that means that we plug in t for all the x’s.
Here is this evaluation. f ( t ) = t 2 - 2t + 8 Note that in this case this is pretty much the same thing as our original function, except this time
we’re using t as a variable.
[Return to Problems]
© 2007 Paul Dawkins 179 http://tutorial.math.lamar.edu/terms.aspx College Algebra (e) f ( t + 1) and f ( x + 1)
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12