The interval notation for these solutions is 2 or

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Unformatted text preview: lt; and get a similar result. In general we have the following formulas to use here, If p £ b, b > 0 then -b £ p £ b If p < b, b > 0 then -b < p < b Notice that this does require b to be positive just as we did with equations. Let’s take a look at a couple of examples. Example 1 Solve each of the following. (a) 2 x - 4 < 10 [Solution] (b) 9m + 2 £ 1 [Solution] (c) 3 - 2 z £ 5 [Solution] Solution (a) 2 x - 4 < 10 There really isn’t much to do other than plug into the formula. As with equations p simply represents whatever is inside the absolute value bars. So, with this first one we have, -10 < 2 x - 4 < 10 Now, this is nothing more than a fairly simply double inequality to solve so let’s do that. -6 < 2 x < 14 -3 < x < 7 The interval notation for this solution is ( -3, 7 ) . [Return to Problems] © 2007 Paul Dawkins 147 http://tutorial.math.lamar.edu/terms.aspx College Algebra (b) 9m + 2 £ 1 Not much to do here. -1 £ 9 m + 2 £ 1 - 3 £ 9 m £ -1 1 1 - £m£3 9 é1 ë 1ù The interval notation is ê...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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