Alg_Complete

# The problem is that both of these solution methods

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: e here. The main difference of course is that the something that is squared isn’t a single variable it is something else. So, here is the application of the square root property for this equation. 2t - 9 = ± 5 Now, we just need to solve for t and despite the “plus or minus” in the equation it works the same way we would solve any linear equation. We will add 9 to both sides and then divide by a 2. 2t = 9 ± 5 t= ( ) 1 9 5 9± 5 = ± 2 22 Note that we multiplied the fraction through the parenthesis for the final answer. We will usually do this in these problems. Also, do NOT convert these to decimals unless you are asked to. This © 2007 Paul Dawkins 91 http://tutorial.math.lamar.edu/terms.aspx College Algebra is the standard form for these answers. With that being said we should convert them to decimals just to make sure that you can. Here are the decimal values of the two solutions. t= 9 5 + = 5.61803 22 and t= 9 5 = 3.38197 22 [Return to Problems] (e) ( 3 x + 10 ) + 81 = 0 2 In this final part we’ll not put much in the way of details into the work. (...
View Full Document

## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online