Alg_Complete

# The word equation for this problem is portion of job

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: From the figure it looks like we’ve got the following word equation. æ Distance ö æ Distance ö 100 + ç ÷=ç ÷ è of Boat B ø è of Boat A ø Upon plugging in the standard formula for the distance gives, æ Rate of ö æ Time of ö æ Rate of ö æ Time of ö 100 + ç ÷ç ÷=ç ÷ç ÷ è Boat B ø è Boat B ø è Boat A ø è Boat A ø For this problem we know that the time each is 5 hours and we know that the rate of Boat A is 2r and the rate of Boat B is r. Plugging these into the work equation and solving gives, 100 + ( r ) ( 5 ) = ( 2r ) ( 5 ) 100 + 5r = 10r 100 = 5r 20 = r So, the slower boat is moving at 20 mph and the faster boat is moving at 40 mpg (twice as fast). Work/Rate Problems These problems are actually variants of the Distance/Rate problems that we just got done working. The standard equation that will be needed for these problems is, æ Portion of job ö æ Work ö æ Time Spent ö ç ÷=ç ÷´ç ÷ è done in given time ø è Rate ø è Working ø As you can see this formula i...
View Full Document

## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online