This time we will combine the work in the previous

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Unformatted text preview: ll. Now, go back to the radical and then use the second and first property of radicals as we did in the first example. 18 x 6 y11 = 9 ( x3 ) 2 ( y ) (2y) = 52 9 (x ) ( y ) 32 52 2 y = 3x3 y 5 2 y Note that we used the fact that the second property can be expanded out to as many terms as we have in the product under the radical. Also, don’t get excited that there are no x’s under the radical in the final answer. This will happen on occasion. [Return to Problems] (d) 4 32 x9 y 5 z12 This one is similar to the previous part except the index is now a 4. So, instead of get perfect squares we want powers of 4. This time we will combine the work in the previous part into one step. 4 32 x9 y 5 z12 = 4 16 x8 y 4 z12 ( 2 xy ) = 4 16 4 ( x 2 ) 4 4 y4 4 ( z3 ) 4 4 2 xy = 2 x 2 y z 3 4 2 xy [Return to Problems] (e) 5 x12 y 4 z 24 Again this one is similar to the previous two parts. 5 x12 y 4 z 24 = 5 x10 z 20 ( x 2 y 4 z 4 ) = 5 (x ) (z ) 2 55 4 55 x2 y 4 z 4 = x2 z 4 5 x2 y 4 z 4 In this case don’t get exci...
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