To finish this we just need to determine the two

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Unformatted text preview: (a) x 2 + 2 x - 15 [Solution] (b) x 2 - 10 x + 24 [Solution] (c) x 2 + 6 x + 9 [Solution] (d) x 2 + 5 x + 1 [Solution] (e) 3 x 2 + 2 x - 8 [Solution] (f) 5 x 2 - 17 x + 6 [Solution] (g) 4 x 2 + 10 x - 6 [Solution] © 2007 Paul Dawkins 34 http://tutorial.math.lamar.edu/terms.aspx College Algebra Solution (a) x 2 + 2 x - 15 Okay since the first term is x2 we know that the factoring must take the form. ( )( x + ) x 2 + 2 x - 15 = x + We know that it will take this form because when we multiply the two linear terms the first term must be x2 and the only way to get that to show up is to multiply x by x. Therefore, the first term in each factor must be an x. To finish this we just need to determine the two numbers that need to go in the blank spots. We can narrow down the possibilities considerably. Upon multiplying the two factors out these two numbers will need to multiply out to get -15. In other words these two numbers must be factors of -15. Here are all the possible ways to factor -15 using only intege...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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