This preview shows page 1. Sign up to view the full content.
Unformatted text preview: olynomial is, x 2  10 x + 24 = ( x  4 ) ( x  6 ) [Return to Problems] (c) x 2 + 6 x + 9
Again, let’s start with the initial form, ( x2 + 6 x + 9 = x + )( x + ) This time we need two numbers that multiply to get 9 and add to get 6. In this case 3 and 3 will
be the correct pair of numbers. Don’t forget that the two numbers can be the same number on
occasion as they are here.
Here is the factored form for this polynomial.
© 2007 Paul Dawkins 35 http://tutorial.math.lamar.edu/terms.aspx College Algebra x 2 + 6 x + 9 = ( x + 3)( x + 3) = ( x + 3) 2 Note as well that we further simplified the factoring to acknowledge that it is a perfect square.
You should always do this when it happens.
[Return to Problems] (d) x 2 + 5 x + 1
Once again, here is the initial form, ( x2 + 5x + 1 = x + )( x + ) Okay, this time we need two numbers that multiply to get 1 and add to get 5. There aren’t two
integers that will do this and so this quadratic doesn’t factor.
This will happen on occasion so don...
View
Full
Document
This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
 Spring '12
 MrVinh

Click to edit the document details