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Unformatted text preview: ing functions.
(a) g ( x ) = x 2 + 3 [Solution]
(b) f ( x ) = x -5 [Solution] Solution
The first thing to do here is graph the function without the constant which by this point should be
fairly simple for you. Then shift accordingly.
(a) g ( x ) = x 2 + 3
In this case we first need to graph x 2 (the dotted line on the graph below) and then pick this up
and shift it upwards by 3. Coordinate wise this will mean adding 3 onto all the y coordinates of
points on x 2 .
Here is the sketch for this one. (b) f ( x ) = [Return to Problems] x -5 © 2007 Paul Dawkins 227 http://tutorial.math.lamar.edu/terms.aspx College Algebra Okay, in this case we’re going to be shifting the graph of x (the dotted line on the graph
below) down by 5. Again, from a coordinate standpoint this means that we subtract 5 from the y
coordinates of points on x. Here is this graph. [Return to Problems] So, vertical shifts aren’t all that bad if we can graph the “base” function first. Note as well that if
you’re not sure that you...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12