Alg_Complete

# A g x x 2 solution b h x x solution solution a

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ing functions. (a) g ( x ) = x 2 + 3 [Solution] (b) f ( x ) = x -5 [Solution] Solution The first thing to do here is graph the function without the constant which by this point should be fairly simple for you. Then shift accordingly. (a) g ( x ) = x 2 + 3 In this case we first need to graph x 2 (the dotted line on the graph below) and then pick this up and shift it upwards by 3. Coordinate wise this will mean adding 3 onto all the y coordinates of points on x 2 . Here is the sketch for this one. (b) f ( x ) = [Return to Problems] x -5 © 2007 Paul Dawkins 227 http://tutorial.math.lamar.edu/terms.aspx College Algebra Okay, in this case we’re going to be shifting the graph of x (the dotted line on the graph below) down by 5. Again, from a coordinate standpoint this means that we subtract 5 from the y coordinates of points on x. Here is this graph. [Return to Problems] So, vertical shifts aren’t all that bad if we can graph the “base” function first. Note as well that if you’re not sure that you...
View Full Document

## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

Ask a homework question - tutors are online