A x 2 y 2 1 solution b x 2 y 3 4 solution 2 c

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Unformatted text preview: pendicular to the line given by 10 y + 3 x = -2 . [Solution] Solution In both parts we are going to need the slope of the line given by 10 y + 3 x = -2 so let’s actually find that before we get into the individual parts. 10 y = -3x - 2 3 1 y =- x10 5 Þ m1 = - 3 10 Now, let’s work the example. © 2007 Paul Dawkins 167 http://tutorial.math.lamar.edu/terms.aspx College Algebra (a) parallel to the line given by 10 y + 3 x = -2 In this case the new line is to be parallel to the line given by 10 y + 3 x = -2 and so it must have the same slope as this line. Therefore we know that, m2 = - 3 10 Now, we’ve got a point on the new line, ( 8, 2 ) , and we know the slope of the new line, - 3 , so 10 we can use the point-slope form of the line to write down the equation of the new line. Here is the equation, 3 ( x - 8) 10 3 24 = 2- x+ 10 10 3 44 = - x+ 10 10 3 22 y = - x+ 10 5 y = 2- [Return to Problems] (b) perpendicular to the line given by 10 y + 3 x = -2 For this part we want the line to be perpendicular to 10 y + 3 x = -2 and so we kn...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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