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Unformatted text preview: remaining problems we
will just do the work without as much explanation.
(a) x 2 - 6 x + 1 = 0
So, let’s get started.
Step 1 : Divide the equation by the coefficient of the x2 term. Recall that completing the square
required a coefficient of one on this term and this will guarantee that we will get that. We don’t
need to do that for this equation however.
Step 2 : Set the equation up so that the x’s are on the left side and the constant is on the right side. x 2 - 6 x = -1
Step 3 : Complete the square on the left side. However, this time we will need to add the number
to both sides of the equal sign instead of just the left side. This is because we have to remember
the rule that what we do to one side of an equation we need to do to the other side of the equation.
First, here is the number we add to both sides.
© 2007 Paul Dawkins 94 http://tutorial.math.lamar.edu/terms.aspx College Algebra 2 2
æ -6 ö
ç ÷ = ( -3 ) = 9
è2ø Now, complete the square. x 2 - 6 x + 9 = -1 + 9 ( x - 3) 2...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12