Aspx college algebra also along those lines we didnt

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Unformatted text preview: 685202 = ln ( 2 ) - 6 ¹ ln ( 2 - 6 ) = ln ( -4 ) can't be done Be very careful with this mistake. It is easy to make when you aren’t paying attention to what you’re doing or are in a hurry. [Return to Problems] (d) 105- x = 8 The equation in this part is similar to the previous part except this time we’ve got a base of 10 and so recalling the fact that, log10 f ( x ) = f ( x ) it makes more sense to use common logarithms this time around. Here is the work for this equation. log105- x = log 8 5 - x = log 8 5 - log 8 = x Þ x = 5 - 0.903089987 = 4.096910013 This could have been done with natural logarithms but the work would have been messier. [Return to Problems] (e) 5e 2 z + 4 - 8 = 0 With this final equation we’ve got a couple of issues. First we’ll need to move the number over to the other side. In order to take the logarithm of both sides we need to have the exponential on one side by itself. Doing this gives, © 2007 Paul Dawkins 300 College Algebra 5e2 z + 4 = 8 Next, we’ve got to get a coefficient...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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