Ax by p cx dy q where any of the constants can be

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Unformatted text preview: fter a half of a day? [Solution] (b) How long will it take before there are 10000 bacteria in the colony? [Solution] Solution Here is the equation for this starting amount of bacteria. Q = 500 e0.195 t (a) How many bacteria are there after a half of a day? In this case if we want the number of bacteria after half of a day we will need to use t = 12 since t is in hours. So, to get the answer to this part we just need to plug t into the equation. Q = 500 e0.195 (12 ) = 500 (10.3812365627 ) = 5190.618 So, since a fractional population doesn’t make much sense we’ll say that after half of a day there are 5190 of the bacteria present. [Return to Problems] (b) How long will it take before there are 10000 bacteria in the colony? Do NOT make the mistake of assuming that it will be approximately 1 day for this answer based on the answer to the previous part. With exponential growth things just don’t work that way as we’ll see. In order to answer this part we will need to solve the following exponential equation. 10000 = 500 e0.195 t © 2007 P...
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