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Unformatted text preview: e there is a y2 term by itself we had to
have k = 0 . At this point we also know that the vertices are ( -2,3) and ( -2, -3) .
In order to see the slopes of the asymptotes let’s rewrite the equation a little. y2 ( x + 2)
= ±3 . The equations of the asymptotes are then,
y = 0 + 3 ( x + 2 ) = 3x + 6
y = 0 - 3 ( x + 2 ) = -3 x - 6 So, the slopes of the asymptotes are ± Here is the sketch of this hyperbola. © 2007 Paul Dawkins 222 http://tutorial.math.lamar.edu/terms.aspx College Algebra [Return to Problems] © 2007 Paul Dawkins 223 http://tutorial.math.lamar.edu/terms.aspx College Algebra Miscellaneous Functions
The point of this section is to introduce you to some other functions that don’t really require the
work to graph that the ones that we’ve looked at to this point in this chapter. For most of these
all that we’ll need to do is evaluate the function as some x’s and the plot the points.
This is probably the easiest function that we’ll ever graph and yet it is one of the functions that
tend to cause problems for students.
The most general...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12