Mathlamaredutermsaspx college algebra 3 9 x2 3 6 x2 3

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Unformatted text preview: ted about the fact that all the y’s stayed under the radical. That will happen on occasion. [Return to Problems] (f) 3 9 x 2 3 6 x 2 This last part seems a little tricky. Individually both of the radicals are in simplified form. However, there is often an unspoken rule for simplification. The unspoken rule is that we should have as few radicals in the problem as possible. In this case that means that we can use the second property of radicals to combine the two radicals into one radical and then we’ll see if there is any simplification that needs to be done. © 2007 Paul Dawkins 20 College Algebra 3 9 x2 3 6 x2 = 3 (9 x ) ( 6x ) = 2 2 3 54 x 4 Now that it’s in this form we can do some simplification. 9 x 2 3 6 x 2 = 3 27 x3 ( 2 x ) = 3 27 x3 3 2 x = 3 x 3 2 x 3 [Return to Problems] Before moving into a set of examples illustrating the last two simplification rules we need to talk briefly about adding/subtracting/multiplying radicals. Performing these operations with radicals is much the same as performing these operations with polynomi...
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