Mathlamaredutermsaspx college algebra a 1 5 1x 1 2x

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Unformatted text preview: urn to Problems] (e) 3 x 2 = 2 x + 8 Now that we’ve done quite a few of these, we won’t be putting in as much detail for the next two problems. Here is the work for this equation. © 2007 Paul Dawkins 87 http://tutorial.math.lamar.edu/terms.aspx College Algebra 3x2 - 2 x - 8 = 0 ( 3x + 4 )( x - 2 ) = 0 Þ x=- 4 and x = 2 3 [Return to Problems] (f) 10 z 2 + 19 z + 6 = 0 Again, factor and use the zero factor property for this one. 10 z 2 + 19 z + 6 = 0 ( 5 z + 2 )( 2 z + 3) = 0 Þ z=- 2 and 5 z=- 3 2 [Return to Problems] (g) 5 x 2 = 2 x This one always seems to cause trouble for students even though it’s really not too bad. First off. DO NOT CANCEL AN x FROM BOTH SIDES!!!! Do you get the idea that might be bad? It is. If you cancel an x from both sides, you WILL miss a solution so don’t do it. Remember we are solving by factoring here so let’s first get everything on one side of the equal sign. 5x2 - 2 x = 0 Now, notice that all we can do for factoring is to factor an x out of everything. Doing this gives, x (5x...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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