Alg_Complete

# Mathlamaredutermsaspx college algebra x 0 and the

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Unformatted text preview: to the next point that we’ve got, x = 1 , the graph must have another turning point somewhere between x = 0 and x = 1 since the graph is higher at x = 1 than at x = 0 . Just where this turning point will occur is very difficult to determine at this level so we won’t worry © 2007 Paul Dawkins 258 http://tutorial.math.lamar.edu/terms.aspx College Algebra about trying to find it. In fact, determining this point usually requires some Calculus. So, we are moving to the right and the function is increasing. The next point that we hit is the xintercept at x = 2 and this one crosses the x-axis so we know that there won’t be a turning point here as there was at the first x-intercept. Therefore, the graph will continue to increase through this point until we hit the final point that we evaluated the function at, x = 3 . At this point we’ve hit all the x-intercepts and we know that the graph will increase without bound at the right end and so it looks like all we need to do is sketch in an increasing curve. Here is a sketch of the polynomial. Note that one of the...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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