U z u2 z 2 z the equation then becomes u 2

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Unformatted text preview: ar.edu/terms.aspx College Algebra So, the basic process is to check that the equation is reducible to quadratic in form then make a quick substitution to turn it into a quadratic equation. We solve the new equation for u, the variable from the substitution, and then use these solutions and the substitution definition to get the solutions to the equation that we really want. In most cases to make the check that it’s reducible to quadratic in form all that we really need to do is to check that one of the exponents is twice the other. There is one exception to this that we’ll see here once we get into a set of examples. Also, once you get “good” at these you often don’t really need to do the substitution either. We will do them to make sure that the work is clear. However, these problems can be done without the substitution in many cases. Example 2 Solve each of the following equations. 2 3 1 3 (a) x - 2 x - 15 = 0 [Solution] (b) y -6 - 9 y -3 + 8 = 0 [Solution] (c) z - 9 z + 14 = 0...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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