Alg_Complete

# X 7 2 x 6 x5 x3 x 1 8 x5 x 2 2 x 1 x3

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Unformatted text preview: to so we flipped the x and the “-1”. Finally, we dropped the “-1” and just went back to a negative sign in the front. Typically when we factor out minus signs we skip all the intermediate steps and go straight to the final step. Let’s now get back to the problem. The rational expression becomes, x 2 - 25 ( x - 5 ) ( x + 5 ) = 5x - x2 - x ( x - 5) At this point we can see that we do have a common factor and so we can cancel the x-5. x 2 - 25 x + 5 x+5 = =2 5x - x -x x [Return to Problems] © 2007 Paul Dawkins 43 http://tutorial.math.lamar.edu/terms.aspx College Algebra (c) x 7 + 2 x 6 + x5 x3 ( x + 1) 8 In this case the denominator is already factored for us to make our life easier. All we need to do is factor the numerator. x 7 + 2 x 6 + x5 x3 ( x + 1) 8 = x5 ( x 2 + 2 x + 1) x3 ( x + 1) 8 x 5 ( x + 1) x3 ( x + 1) = 2 8 Now we reach the point of this part of the example. There are 5 x’s in the numerator and 3 in the denominator so when we cancel there will be 2 left in the numer...
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