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Unformatted text preview: ll the other terms on the other side. Once
this is done we then factor out a y and divide by the coefficient. Again, we would prefer a
decimal answer so let’s get that.
© 2007 Paul Dawkins 299 http://tutorial.math.lamar.edu/terms.aspx College Algebra y=- ln 2
4 ln 2 - ln 3
4 ( 0.693147181) - 1.098612289
[Return to Problems] (c) et + 6 = 2
Now, this one is a little easier than the previous one. Again, we’ll take the natural logarithm of
both sides. ln et + 6 = ln 2
Notice that we didn’t take the exponent out of this one. That is because we want to use the
following property with this one. ln e f ( x ) = f ( x ) We saw this in the previous section (in more general form) and by using this here we will make
our life significantly easier. Using this property gives, t + 6 = ln 2 t = ln ( 2 ) - 6 = 0.69314718 - 6 = -5.30685202
Notice the parenthesis around the 2 in the logarithm this time. They are there to make sure that
we don’t make the following mistake. -5.30...
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This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.
- Spring '12