Alg_Complete

# X x 1 3 x 12 x 2 x 3x 12 0 x 2 4 x 12

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Unformatted text preview: ll the other terms on the other side. Once this is done we then factor out a y and divide by the coefficient. Again, we would prefer a decimal answer so let’s get that. © 2007 Paul Dawkins 299 http://tutorial.math.lamar.edu/terms.aspx College Algebra y=- ln 2 0.693147181 == -0.414072245 4 ln 2 - ln 3 4 ( 0.693147181) - 1.098612289 [Return to Problems] (c) et + 6 = 2 Now, this one is a little easier than the previous one. Again, we’ll take the natural logarithm of both sides. ln et + 6 = ln 2 Notice that we didn’t take the exponent out of this one. That is because we want to use the following property with this one. ln e f ( x ) = f ( x ) We saw this in the previous section (in more general form) and by using this here we will make our life significantly easier. Using this property gives, t + 6 = ln 2 t = ln ( 2 ) - 6 = 0.69314718 - 6 = -5.30685202 Notice the parenthesis around the 2 in the logarithm this time. They are there to make sure that we don’t make the following mistake. -5.30...
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## This note was uploaded on 06/06/2012 for the course ICT 4 taught by Professor Mrvinh during the Spring '12 term at Hanoi University of Technology.

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