Homework #5

Homework #5 - H5 Mistrth 3.13 The Porsche starts from rost...

Info iconThis preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: H5 Mistrth 3.13 The Porsche starts from rost at tinth = t}. During the first It] seconds of its motion, its velocity in kmt’h is given as a function of time by 1: = 22.3t - (1.331", where: is in seconds. (it) What is the car‘s maximum acceleration in mfsz. and when does it occur? [b] What distance in km does the car [rave] during the ID seconds? aft) harness-Es n.4— f tn‘Lvfidfli-EJ— roam” «Jf' f: 0 d. aha-1 [3.23 [U September 2003, Tony Sehumaeher slarled from rest and drove a quarler mile {I33} II} in 4.4533 s in a National Eiel Retl Asseeiutlen race. His 5pced as he crossed the finish line was 328.54 mir'h. Assume that the eer‘s neeelernlien can he expressed by :1 linear function affirm: 0: = h + N. Ca} FILM? in + c Lb) FLA-<9 '5 F (0;) Emma a=a({’) M‘s-4*. {-1.3 2,4 @ f‘ZSLe, [3.3.3r If'taI - 1 rad and dam: = l mills, what is the velocity at" P relative to (5"? Strategy: You can write the position of.” relative tn 0 as .s={2 PE}CDSH 1 (2 fileosfl and then take the derivative of this expression with respect to time to determine the velocity. s E:ij e=zfzm® t " :(‘i’wL9H>‘f “ME we law atria-flaw Ma Rant)» til— mjKC-srr fflfi‘tfimog 540—9? Mjwtw with M 1C“ gm»; 9-53 M34: FRI-r3314“ etc-nap Cumin. vale, 13.41 An unginccr designing :1 SySlCI'II to control a router for a nmchining process nmdcls the system 30 that the . . . 'l . . . . . . . . mulcr‘s ucuulcrnunn {:11 mm") dunng an Interval nf‘llmc 15 gwm by a "(1.41; where I' Is the wluulty at [111: muterin inffi. When I = f}. Ihe lmsilion {5.1: = f} and Iht: whicin is r— 2 infiH. W'hm is the pnsilinn Ell r = 3 5'? fl H—E/hemk-Wua '5‘"?— |3_54 The acceleration Oran object is given as a function of its posilion in Fcct by u = iv: IL’HE. thn .1: U. its ‘v'CllJL‘ilj' 1's 1’ 1 WE. What is the vclucily uf'thc abjch when .x- — 2 11‘? W m kw mi» Mgmm % W." w... MEI-E 21-S- éfl—t a =HC‘E) =2 (Z 51 J-FWLL f ...
View Full Document

Page1 / 5

Homework #5 - H5 Mistrth 3.13 The Porsche starts from rost...

This preview shows document pages 1 - 5. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online