University Physics with Modern Physics with Mastering Physics (11th Edition)

  • Homework Help
  • PresidentHackerCaribou10582
  • 1

Info icon This preview shows page 1. Sign up to view the full content.

5.76: To answer the question, 0 v must be found and compared with hr). km (72 s m 20 The kinematics relationship 2 0 2 v ax - = is useful, but we also need a . The acceleration must be large enough to cause the box to begin sliding, and so we must use the force of static friction in Newton’s Second Law:
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: . or , s s g a ma mg μ-= ≤-Then, , ) ( 2 2 s v x g μ-=-or . m) 47 )( s m 8 . 9 )( 30 (. 2 2 2 s = = gx v Hence, , h km 60 s m 6 . 16 = = v which is less than 72 km/h, so do you not go to jail....
View Full Document

  • '
  • NoProfessor
  • 9.8 m, 20 M, 60 km, 16.6 m, 47 m

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern