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**Unformatted text preview: **5.78: a) Taking components along the direction of the plane's descent, f = w sin and L = w cos . b) Dividing one of these relations by the other cancels the weight, so tan = f L . c) The distance will be the initial altitude divided by the tangent 1300 N of . f = L tan and L = w cos , therefore sin = f w = 12,900 N g and so = 5.78. This makes the horizontal distance (2500 m) tan(5.78) = 24.7 km. d) If the drag is reduced, the angle is reduced, and the plane goes further. ...

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