In this reaction a pair of electrons hydride ion is

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Unformatted text preview: o produce acetyl-coA (2C) and 1 CO2. In this reaction, a pair of electrons (hydride ion) is transferred to NAD+ to produce 1 NADH. (2) Then, the 2 C’s of the acetyl group enter the cycle by transfer to oxaloacetate (4C) to produce citric acid (6C). (3) Citrate is converted to isocitrate (6C), with no recovery of energy. (4) Isocitrate is then converted to áketoglutarate, yielding another pair of electrons that reduce an NAD+ to NADH, and producing another CO2. (5) Next, á-ketoglutarate is converted to succinyl-coA, which yields another pair of electrons that reduce an NAD+ to NADH and produces another CO2. (6) Then succinyl-CoA is converted to succinate; this reaction is coupled to the synthesis of one GTP. (7) Succinate is then converted to fumarate, which yields a pair of electrons that are harvested not by NAD+, but by FADH (=> FADH2). (8) Fumarate is converted to malate, with no coupled reaction. (9) Maleate is converted to oxaloacetate, which yields a pair of electrons that are harvested by NAD+ => NADH This returns the molecule that we started with, which can continue the cycle by combining with another molecule of acetyl-CoA... (B) So what has happened here? Carbons in, high energy electrons out (see panel 13-2). (1) A high energy 3-carbon compound (pyruvate) enters the matrix, a 2-carbon acetyl group gets fed into the cycle and is systematica...
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This note was uploaded on 06/12/2012 for the course BIOLOGY 231 taught by Professor Petethollenbeck during the Fall '10 term at Purdue.

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