**Unformatted text preview: **= a v v t Using Newton’s Second Law for the vertical direction N 1400 or N 5 . 1447 s m )) 7 . 3 ( kg)(5.95 150 ( ) ( 2 PAPSv PAPSv =--= + =-= = + g a m mg ma F ma mg F which is the vertical component of the PAPS force. The vehicle must also be brought to a stop horizontally in 12.4 seconds; the acceleration needed to do this is 2 2 s m 66 . 2 s 4 . 12 s m 33 =-=-= t v v a and the force needed is N 399 ) s m kg)(2.66 150 ( 2 PAPSh = = = ma F or 400 N, since there are no other horizontal forces....

View
Full
Document