problem05_84

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.84: Considering positive accelerations to be to the right (up and to the right for the left- hand block, down and to the right for the right-hand block), the forces along the inclines and the accelerations are related by , kg) 50 ( 53 sin kg) (50 , kg) 100 ( 30 sin kg) 100 ( a T g a g T = - ° = ° - where T is the tension in the cord and a the mutual magnitude of acceleration. Adding these relations, . 067 . 0 or , kg) 100 kg 50 ( ) 30 sin kg 100 53 sin kg 50 ( g a a g - = + = ° - ° a) Since a comes out negative, the blocks will slide to the left; the 100-kg block will slide down. Of course,
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Unformatted text preview: if coordinates had been chosen so that positive accelerations were to the left, a would be . 067 . g + b) . s m 658 . ) s m 80 . 9 ( 067 . 2 2 = c) Substituting the value of a (including the proper sign, depending on choice of coordinates) into either of the above relations involving T yields 424 N....
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