sampleEXAM2_solns

# sampleEXAM2_solns - TAM 211/210 BL1 Fall 2004 Practice Exam...

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TAM 211/210 BL1 Fall, 2004 Name: Practice Exam 2 Section: To receive full credit you must show all your work 1. What is single force resultant to the distributed force system? Assume d and q 0 are known. (25 points) First, let’s find the single force resultant to two the changing distributed loads individually: For the first, the equivalent force/couple system at the wall is: () 3 / ˆ 3 / ˆ ˆ ˆ 3 0 3 0 2 d q x q dx x q F o d x o d x o y j j j j F = = = = = = 4 / ˆ 4 / ˆ ˆ 4 0 4 0 2 , d q x q dx x xq o d x o d x o O r k k k M = = = = = so a single force resultant of 3 / ˆ 3 d q o j could be applied at ( ) ( ) 4 3 3 / 4 / 3 4 d d q d q x o o = = For the second, a single force resultant of ( ) 3 2 4 ˆ 4 ˆ d q d d q o o j j = could be applied at d d d x 3 2 / 4 = + = Thus, an equipollent system of two forces is: Fort these two, the single force resultant will have magnitude F = q 0 d 3 /3 + 4q 0 d 3 =(4 1/3) q 0 d 3 The equivalent force/couple system at the wall is 3 / 13 ˆ 3 d q o j F = , ()( ) ( ) k k j i j i F r M 4 / 49 4 12 / 1 3 4 3 3 / 4 / 3 4 4 3 3 1 , d q d q d q d d q d o o o o N i i OA O r forces i = + = × + × = × = = v v v so a single

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sampleEXAM2_solns - TAM 211/210 BL1 Fall 2004 Practice Exam...

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