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Unformatted text preview: 2 V 1 = 2 . 75 , V 1 = 2 . 75 2 = 1 . 375 V, V Th = V 1. 25(0 . 5) = 1 . 375. 125 = 1 . 25 V , V Th = 1 . 25 V I N = V Th R Th = 1 . 25 1 = 1 . 25 A I N = 1 . 25 A Note: Short circuit current I N can also be computed by shorting a,b. ( V 13 . 5 + V 1 . 5 + V 1V 2 . 25 = 0) . 5 , V 13 + V 1 + 2 V 12 V 2 = 0 , 4 V 12 V 2 = 3 , ( V 2V 1 . 25 + 0 . 5 + V 2 . 5 = 0) . 5 , 2 V 22 V 1 + 0 . 25 + V 2 = 0 , 3 V 22 V 1 =. 25 ,4 V 1 + 6 V 2 =. 5 Adding the two equations, 4 V 2 = 2 . 5 , V 2 = 0 . 625 V, I N = V 2 . 5 = . 625 . 5 = 1 . 25 A...
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This homework help was uploaded on 04/07/2008 for the course EECE 519 taught by Professor Chandra during the Spring '08 term at Kansas State University.
 Spring '08
 Chandra

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