problem05_87

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.87: See Exercise 5.15 (Atwood’s machine). The 2.00-kg block will accelerate upward at , 7 3 kg 2.00 kg 5.00 kg 00 . 2 kg 00 . 5 g g = + - and the 5.00-kg block will accelerate downward at . 7 3 g Let the initial height above the ground be 0 h ; when the large block hits the ground, the small block will be at a height 0 2
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Unformatted text preview: h , and moving upward with a speed given by . 7 6 2 2 gh ah v = = The small block will continue to rise a distance , 7 3 2 2 h g v = and so the maximum height reached will be m 46 . 1 7 17 7 3 2 = = + h h h , which is 0.860 m above its initial height....
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• NoProfessor
• 2008 albums, 3 g, 2.00 kg, 2.00-kg, 1.46 m, 0.860 m

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