problem05_87

University Physics with Modern Physics with Mastering Physics (11th Edition)

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
5.87: See Exercise 5.15 (Atwood’s machine). The 2.00-kg block will accelerate upward at , 7 3 kg 2.00 kg 5.00 kg 00 . 2 kg 00 . 5 g g = + - and the 5.00-kg block will accelerate downward at . 7 3 g Let the initial height above the ground be 0 h ; when the large block hits the ground, the small block will be at a height 0 2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: h , and moving upward with a speed given by . 7 6 2 2 gh ah v = = The small block will continue to rise a distance , 7 3 2 2 h g v = and so the maximum height reached will be m 46 . 1 7 17 7 3 2 = = + h h h , which is 0.860 m above its initial height....
View Full Document

This document was uploaded on 02/04/2008.

Ask a homework question - tutors are online