problem05_92

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.92: (a) There is a contact force n between the man (mass M ) and the platform (mass m ). The equation of motion for the man is , Ma Mg n T = - + where T is the tension in the rope, and for the platform, T n mg ma - - = . Adding to eliminate n , and rearranging, ). )( ( 2 1 g a m M T + + = This result could be found directly by considering the man- platform combination as a unit, with mass , M m + being pulled upward with a force 2 T due to the two
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Unformatted text preview: ropes on the combination. The tension T in the rope is the same as the force that the man applies to the rope. Numerically, N. 551 ) s m 80 . 9 s m kg)(1.80 25.0 kg . 70 ( 2 1 2 2 = + + = T (b) The end of the rope moves downward 2 m when the platform moves up 1 m, so . 2 platform rope a a-= Relative to the man, the acceleration of the rope is , s m 40 . 5 3 2 = a downward....
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## This document was uploaded on 02/04/2008.

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