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University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.95: a) The same analysis as in Problem 5.90 applies, but with the speed v an unknown. The equations of motion become . sin cos , cos sin s 2 s mg n n R mv n n = - = + β μ β β μ β Dividing to cancel n gives . sin cos cos sin 2 s s Rg v = - + β μ β β μ β Solving for v and substituting numerical values gives s m 9 . 20 = v (note that the value for the coefficient of static friction must be used). b) The same analysis applies, but the friction force must be directed up the bank; this
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Unformatted text preview: has the same algebraic effect as replacing f with f-, or replacing s with s-(although coefficients of friction may certainly never be negative). The result is , sin cos cos sin ) ( s s 2 β β β β gR v +-= and substitution of numerical values gives s. m 5 . 8 = v...
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