This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: homework 10 LEE, BENJAMIN Due: Sep 27 2007, 4:00 am 1 Question 1, chap 26, sect 4. part 1 of 2 10 points A parallelplate capacitor has a charge of 8 . 5 C when charged by a potential difference of 2 . 80 V . a) Find its capacitance. Correct answer: 3 . 03571 10 6 F (tolerance 1 %). Explanation: Let : Q = 8 . 5 C and V 1 = 2 . 80 V . The capacitance is given by C = Q V = 8 . 5 10 6 C 2 . 8 V = 3 . 03571 10 6 F . Question 2, chap 26, sect 4. part 2 of 2 10 points b) How much electrical potential energy is stored when this capacitor is connected to a 1 . 22 V battery? Correct answer: 2 . 25918 10 6 J (tolerance 1 %). Explanation: Let : V 2 = 1 . 22 V PE electric = 1 2 C ( V ) 2 = 1 2 (3 . 03571 10 6 F) (1 . 22 V) 2 = 2 . 25918 10 6 J Question 3, chap 26, sect 4. part 1 of 2 10 points A 3 F capacitor is charged to 80 V. How much energy is stored in the capacitor? Correct answer: 9 . 6 mJ (tolerance 1 %). Explanation: Let : C = 3 F = 3 10 6 F and V = 80 V . The energy is U i = 1 2 C V 2 = 1 2 (3 10 6 F) (80 V) 2 1000 mJ 1 J = 9 . 6 mJ . Question 4, chap 26, sect 4....
View
Full
Document
This note was uploaded on 04/07/2008 for the course PHY 303K taught by Professor Turner during the Fall '07 term at A.T. Still University.
 Fall '07
 Turner
 Capacitance, Charge, Work

Click to edit the document details