{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

# hw10 - homework 10 LEE BENJAMIN Due 4:00 am Question 1 chap...

This preview shows pages 1–2. Sign up to view the full content.

homework 10 – LEE, BENJAMIN – Due: Sep 27 2007, 4:00 am 1 Question 1, chap 26, sect 4. part 1 of 2 10 points A parallel-plate capacitor has a charge of 8 . 5 μ C when charged by a potential difference of 2 . 80 V . a) Find its capacitance. Correct answer: 3 . 03571 × 10 6 F (tolerance ± 1 %). Explanation: Let : Q = 8 . 5 μ C and Δ V 1 = 2 . 80 V . The capacitance is given by C = Q Δ V = 8 . 5 × 10 6 C 2 . 8 V = 3 . 03571 × 10 6 F . Question 2, chap 26, sect 4. part 2 of 2 10 points b) How much electrical potential energy is stored when this capacitor is connected to a 1 . 22 V battery? Correct answer: 2 . 25918 × 10 6 J (tolerance ± 1 %). Explanation: Let : Δ V 2 = 1 . 22 V PE electric = 1 2 C V ) 2 = 1 2 (3 . 03571 × 10 6 F) (1 . 22 V) 2 = 2 . 25918 × 10 6 J Question 3, chap 26, sect 4. part 1 of 2 10 points A 3 μ F capacitor is charged to 80 V. How much energy is stored in the capacitor? Correct answer: 9 . 6 mJ (tolerance ± 1 %). Explanation: Let : C = 3 μ F = 3 × 10 6 F and V = 80 V . The energy is U i = 1 2 C V 2 = 1 2 (3 × 10 6 F) (80 V) 2 × 1000 mJ 1 J = 9 . 6 mJ . Question 4, chap 26, sect 4. part 2 of 2 10 points How much additional energy is required to charge the capacitor from 80 V to 210 V?

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

hw10 - homework 10 LEE BENJAMIN Due 4:00 am Question 1 chap...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online