problem05_p104

University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.104: Recognizing the geometry of a 3-4-5 right triangle simplifies the calculation. For instance, the radius of the circle of the mass’ motion is 0.75 m. a) Balancing the vertical force, , 5 4 L 5 4 U w T T = - so N. 0 . 31 ) s m (9.80 kg) 00 . 4 ( 4 5 N 0 . 80 4 5 2 U L = - = - = w T T b) The net inward force is N. 6 . 66 L 5 3 U 5 3 = + = T T F Solving 2 2 4 rad T R m ma F π = = for the period T , s, 334 . 1 N) (66.6 m) (0.75 kg) 00 . 4 ( 2 2 = = = π F mR π T or 0.02223 min, so the system makes 45.0 rev/min. c) When the lower string becomes
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Unformatted text preview: slack, the system is the same as the conical pendulum considered in Example 5.22. With , 800 . cos = the period is s, 007 . 2 ) s m (9.80 (0.800) m) 25 . 1 ( 2 2 = = T which is the same as min. rev 9 . 29 d) The system will still be the same as a conical pendulum, but the block will drop to a smaller angle....
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This document was uploaded on 02/04/2008.

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