problem05_p105

# University Physics with Modern Physics with Mastering Physics (11th Edition)

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5.105: a) Newton’s 2nd law gives , y y kv mg dt dv m - = where t v k mg = - = - y v v t t y y dt m k v v dv 0 0 This is the same expression used in the derivation of Eq. (5.10), except the lower limit in the velocity integral is the initial speed 0 v instead of zero. Evaluating the integrals and rearranging gives ) 1 ( t 0 m kt m kt e v e v v - - - + = Note that at 0 t = this expression says 0 v v y = and at α t it says . t v v y b) The downward gravity force is larger than the upward fluid resistance force so the acceleration is downward, until the fluid resistance force equals gravity when the

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Unformatted text preview: terminal speed is reached. The object speeds up until t v v y = . Take y + to be downward. c) The upward resistance force is larger than the downward gravity force so the acceleration is upward and the object slows down, until the fluid resistance force equals gravity when the terminal speed is reached. Take y + to be downward. d) When t v v = the acceleration at = t is zero and remains zero; the velocity is constant and equal to the terminal velocity....
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## This document was uploaded on 02/04/2008.

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problem05_p105 - terminal speed is reached. The object...

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