5.110:
The passenger’s velocity is
s.
m
80
.
8
2
=
=
t
R
π
v
The vertical component of the
seat’s force must balance the passenger’s weight and the horizontal component must
provide the centripetal force. Therefore
:
N
188
cos
N
833
sin
2
seat
seat
=
=
=
=
R
mv
θ
F
mg
θ
F
Therefore
°
=
=
=
3
.
77
4.43;
N
188
N
833
tan
θ
θ
above the horizontal. The magnitude of
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 Force, net force, Passenger

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