# However kcl must be satised at a supernode like any

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ted differently. Why? Because an essential component of nodal analysis is applying KCL, which requires knowing the current through each element. There is no way of knowing the current through a voltage source in advance. However, KCL must be satisﬁed at a supernode like any other node. Hence, at the supernode in Fig. 3.7, i1 + i4 = i2 + i3 (3.11a) or v 1 − v2 v 1 − v3 v2 − 0 v3 − 0 (3.11b) + = + 2 4 8 6 To apply Kirchhoff ’s voltage law to the supernode in Fig. 3.7, we redraw the circuit as shown in Fig. 3.8. Going around the loop in the clockwise direction gives −v2 + 5 + v3 = 0 ⇒ v2 − v3 = 5 | v v From Eqs. (3.10), (3.11b), and (3.12), we obtain the node voltages. | e-Text Main Menu | Textbook Table of Contents | 5V + +− + v2 − (3.12) Figure 3.8 v3 − Applying KVL to a supernode. Problem Solving Workbook Contents 84 PART 1 DC Circuits Note the following properties of a supernode: 1. The voltage source inside the supernode provides a constraint equation needed to solve for the node voltages. 2. A supernode has no voltage of its...
View Full Document

## This note was uploaded on 07/16/2012 for the course KA KA 2000 taught by Professor Bkav during the Spring '12 term at Cambridge.

Ask a homework question - tutors are online